-8x^2+3x=-10

Solution for -8x^2+3x=-10 equation:

-8x^2+3x=-10

We move all terms to the left:

-8x^2+3x-(-10)=0

We add all the numbers together, and all the variables

-8x^2+3x+10=0

a = -8; b = 3; c = +10;
Δ = b2-4ac
Δ = 32-4·(-8)·10
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{329}}{2*-8}=\frac{-3-\sqrt{329}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{329}}{2*-8}=\frac{-3+\sqrt{329}}{-16}
$